(3X^2+4X+1)(4X+3)=0

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Solution for (3X^2+4X+1)(4X+3)=0 equation: 


Simplifying
(3X2 + 4X + 1)(4X + 3) = 0

Reorder the terms:
(1 + 4X + 3X2)(4X + 3) = 0

Reorder the terms:
(1 + 4X + 3X2)(3 + 4X) = 0

Multiply (1 + 4X + 3X2) * (3 + 4X)
(1(3 + 4X) + 4X * (3 + 4X) + 3X2 * (3 + 4X)) = 0
((3 * 1 + 4X * 1) + 4X * (3 + 4X) + 3X2 * (3 + 4X)) = 0
((3 + 4X) + 4X * (3 + 4X) + 3X2 * (3 + 4X)) = 0
(3 + 4X + (3 * 4X + 4X * 4X) + 3X2 * (3 + 4X)) = 0
(3 + 4X + (12X + 16X2) + 3X2 * (3 + 4X)) = 0
(3 + 4X + 12X + 16X2 + (3 * 3X2 + 4X * 3X2)) = 0
(3 + 4X + 12X + 16X2 + (9X2 + 12X3)) = 0

Combine like terms: 4X + 12X = 16X
(3 + 16X + 16X2 + 9X2 + 12X3) = 0

Combine like terms: 16X2 + 9X2 = 25X2
(3 + 16X + 25X2 + 12X3) = 0

Solving
3 + 16X + 25X2 + 12X3 = 0

Solving for variable 'X'.

The solution to this equation could not be determined.

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